SOLUTION: The length of a rectangle is increased by 60%. By what % would the width have to be decreased to maintain the same area?

Algebra ->  Algebra  -> Rectangles -> SOLUTION: The length of a rectangle is increased by 60%. By what % would the width have to be decreased to maintain the same area?       Log On

Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 169670: The length of a rectangle is increased by 60%. By what % would the width have to be decreased to maintain the same area?
Answer by stanbon(48544) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is increased by 60%. By what % would the width have to be decreased to maintain the same area?
------------------------
Assume the original area = LW
------------------------------
EQUATION after the change:
Let the new width be "x".
(1.6L)x = LW
1.6x = W
x = 0.625W
----------------------
The width would have to be increased by 62.5%
==================================================
Cheers,
Stan H.