SOLUTION: Calculating the dimension of a rectangle with 28 inch length and surrounds a 48 square inch picture. How do I calculate the dimension of the rectangle given this information.

Question 159892: Calculating the dimension of a rectangle with 28 inch length and surrounds a 48 square inch picture. How do I calculate the dimension of the rectangle given this information.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Calculating the dimension of a rectangle with 28 inch length and surrounds a 48 square inch picture. How do I calculate the dimension of the rectangle given this information.
:
Not enough information here. If we knew the width of the border surrounding the
picture or one dimension of the picture, it would be easy
:
If I can make an assumption here, that the picture is 8 by 6 (48sq/in)
then I can find the width of the border: Let x = the width of the border
:
Border + picture length = rectangle length
2x + 8 = 28
2x = 28 - 8
2x = 20
x = 10" is the width of the border
:
Then we can find the width of the rectangle, using the width of the picture
w = 2(10) + 6
w = 20 + 6
w = 26
;
In this case an 8 by 6 inch picture is on a 28 by 26 inch rectangle and has a
10 inch border around the picture
:
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