SOLUTION: A rectangle is 4 feet longer than it is wide and its area is 60 sqft. find it's dimensions?

Question 147500: A rectangle is 4 feet longer than it is wide and its area is 60 sqft. find it's dimensions?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
L = W + 4
L*W = 60
W*(W+4) = 60

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=256 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 6, -10. Here's your graph:

Since a negative width makes no sense, we go with W = 6.
That makes the length = 10.
BTW, it's means "it is", not "it is dimensions"
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