SOLUTION: I need help solving this equation step-by-step. Please help me. (((The perimeter of the retangular is 320ft if the length is 5ft shorter than twice the width. Find its length and

Question 147091: I need help solving this equation step-by-step. Please help me.
(((The perimeter of the retangular is 320ft if the length is 5ft shorter than twice the width. Find its length and width.)))
Found 3 solutions by solver91311, Monarch, 983manoj@gmail.com:
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangle is the distance around the outside. You have two sides of length L and two sides of length W, so . But you also know that and that , so solve for W. Then take that value and substitute it back into to find L.
Answer by Monarch(4)   (Show Source): You can put this solution on YOUR website!
perimeter of the retangular = 2L + 2W
perimeter of the retangular is 320ft
Lets put this in formula
formula 1 - > 2L + 2W = 320
Now L = 2 times Width - 5
formula 2 --> L = 2W - 5
So formula 1 becomes 2(2W - 5) + 2W = 320
4W - 10 + 2W = 320
6W - 10 = 320
6W = 320 + 10
W = 330/6 = 55 ft
Put this value in formula 2 --> L = 2*55 - 5
L= 105 ft
So the length is 105 ft. and width is 55 ft.

Answer by 983manoj@gmail.com(4)   (Show Source): You can put this solution on YOUR website!
assume length = X
assume width =Y
because length is 5ft longer than twice width so X=2Y-5
now 2(X+Y)=320
=>X+Y=160
=>X+(X+5)/2=160(PUTTING VALUE OF X FROM EQUATION X=2Y+5)
=>3X=315
=>X=105
NOW PUT THIS VALUE OF X IN EQUATION X=2Y-5
=>Y=(X+5)/2
=>Y=55
ANSWER== LENGTH=105 AND WIDTH=55
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