SOLUTION: The length of a rectangle is twice its width. If the perimeter of the rectangle is 36 yd, what is the area.
Algebra.Com
Question 139777: The length of a rectangle is twice its width. If the perimeter of the rectangle is 36 yd, what is the area.
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
L=2W
2W+2(2W)=36
2W+4W=36
6W=36
W=36/6
W=6 ANSWER FOR THE WIDTH.
L=2*6=12 ANSWER FOR THE LENGTH.
PROOF:
2*6+2*12=36
12=24=36
36=36
AREA=6*12=72 YDS^2.
RELATED QUESTIONS
The length of a rectangle is 6 yd longer than its width.
If the perimeter of the... (answered by CharlesG2)
The perimeter of a rectangle is 100 yd. If its width is four times its length, what is... (answered by josgarithmetic)
The length of a rectangle is twice its width. If the perimeter of the rectangle is 48 yd (answered by checkley77)
the perimeter of a rectangle is 36 yd. The width is 18 yd less than twice the length.... (answered by mandi08)
The length of a rectangle is 3 yd longer than its width.
If the perimeter of the... (answered by rapaljer)
The length of a rectangle is
2
yd
longer than its width.
If the perimeter of... (answered by IBMath)
The length of a rectangle is
5 yd longer than its width.
If the perimeter of the... (answered by Alan3354)
The length of a rectangle is
3
yd
longer than its width.
If the perimeter of... (answered by Alan3354)
The length of a rectangle is 5 yd longer than its width.
If the perimeter of the... (answered by ankor@dixie-net.com)