SOLUTION: find the length and width of arectangle
area=4square inches
perimeter=8 inches
Algebra.Com
Question 139690: find the length and width of arectangle
area=4square inches
perimeter=8 inches
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
wL=A
2w+2L=P
.
A) wL=4
B) 2w+2L=8
.
A) L=4/w
B)
2w+2(4/w)=8 Substitute
2w + 8/w = 8
2w^2+8=8w multiply each side by w to eliminate fractions.
2w^2-8w+8=0
2(w^2-4w+4)=0
(w-2)^2=0
w=2"
L=4/w=4/2=2"
.
Ed
RELATED QUESTIONS
the preimeter of arectangle is 122inches. The length exceeds the width by 57 inches. find (answered by mananth)
find the length and width of the rectangle
Perimeter: 30 inches; Area: 26 square... (answered by Alan3354,solver91311)
A rectangle has length 40 inches and width 10.2 inches. Find the length in inches of... (answered by LinnW)
Find the area of a rectangle whose length is 6 inches less than 5 times the width and... (answered by solver91311)
A rectangle has an area of 240 square inches and a perimeter of 64 inches. Find the... (answered by richwmiller)
the perimeter of a rectangle is 30 inches, and its area is 56 square inches .find the... (answered by hheuler)
The length of a rectangle is 8 inches less than 4 times the width. The perimeter is 114 (answered by lwsshak3)
The width of a rectangle is 8 inches less than the length. The perimeter is
60 inches.... (answered by Shin123)
the length of arectangle is is 4in grater than the width . the perimeter is 24in find the (answered by stanbon)