SOLUTION: The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?      Log On


   

Question 125189: The length of a rectangle is 1 cm longer than its width. If the diagonal
of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
LET X BE ONE OF THE SIDES.
X+1 IS THE OTHER SIGN.
X^2+(X+1)^2=4^2
X^2+X^2+2X+1=16
2X^2+2X+1-16
2X^2+2X-15=0
USING THE QUADRATIC EQUATION:x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
X=(-2+-SQRT[2^2-4*2*-15])/2*2
X=(-2+-SQRT[4+120 ])/4
X=(-2+-SQRT[124])/4
X=(-2+-11.136)/4
X=(-2+11.136)/4
X=9.136/4
X=2.28 ANSWER.
X=(-2-11.138)/4
X=-13.138/4
X=-3.28 ANSWER.