# SOLUTION: The length of a rectangle is 2 cm more than 5 times its width. If the area of the rectagle is 68cm^2, find the dimensions of the rectagle to the nearest thousandth.

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 Geometry: Rectangles Solvers Lessons Answers archive Quiz In Depth

 Question 119932: The length of a rectangle is 2 cm more than 5 times its width. If the area of the rectagle is 68cm^2, find the dimensions of the rectagle to the nearest thousandth.Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!LENGTH=5W+2 WIDTH=W AREA=W*L 68=W(5W+2) 68=5W^2+2W 5W^2+2W-68=0 USING THE QUADRATIC EQUATION: WE GET: X=(-2+-SQRT[2^2-4*5*-68])/2*5 X=(-2+-SQRT[4+1360])/10 X=(-2+-SQRT1364)/10 X=(-2+-36.932)/10 X=(-2+36.932)/10 X=34.932/10 X=3.493 ANSWER X=(-2-36.932)/10 X=-38.932/10 X=-3.893 ANSWER.