Clearly, no. 



If A = L*W then if you double L and double W, you get: 

 (2L)*(2W) = 4(L*W) = 4*A (i.e. four times the original area).



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If the new swimming pool shape is similar to the old one, then L and W can be scaled by  to achieve a doubling of the area:

 *  =  =  

 

Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
 area = length * width

multiply both sides of the equation by 2 to get:

2 * area = 2 * length * width

2 * length * width = 2 * width * length = (2 * length) * width or (2 * width) * length.

what this suggests is that either the length is multiplied by 2 or the width is multiplied by 2, but not both.

if the length is 35 and the width is 16, then the area is equal to 35 * 16 = 560.

2 time the area = 2 * 560 = 1120.

(2 * width) * length = 35 * 32 = 1120.

either the length is doubled or the width is doubled, but not both.

if both are affected equally, then both the length and the width are multiplied by sqrt(2).

35 * sqrt(2) * 16 * sqrt(2) = 35 * 16 * sqrt(2)^2 = 35 * 16 * 2.

either way, the length and the width are not doubled if the area is doubled.







 

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