SOLUTION: The length of a rectangle is twice it's width. If the width is reduced by 1cm and the length is reduced by 2cm, the area will be 15cm². The dimensions of the original rectangle.

Question 1196616: The length of a rectangle is twice it's width. If the width is reduced by 1cm and the length is reduced by 2cm, the area will be 15cm². The dimensions of the original rectangle.
Found 3 solutions by ewatrrr, ikleyn, Alan3354:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi The length of a rectangle is twice it's width. width w length 2w If the width is reduced by 1cm and the length is reduced by 2cm, the area will be 15cm². A = length*width (2w-2)(w-1) = 15cm² Solve for w, rounding answer as instructed 2w^2 -4w + 2 = 15 Wish You the Best in your Studies.

Answer by ikleyn(52790)   (Show Source): You can put this solution on YOUR website!
.

Let w be the width, in centimeters. Then the length is 2w cm. After changing the dimensions, they become (w-1) cm and (2w-2) cm. The area equation is (w-1)*(2w-2) = 15. Simplify and solve it MENTALLY 2*(w-1)*(w-1) = 15 (w-1)^2 = 15/2 = 7.5 w-1 = w = = 3.74 cm. ANSWER. The dimensions of the original rectangle are 3.74 cm (the width) and 2*3.74 = 7.48 cm (the length).

Solved.

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
The length of a rectangle is twice it's [sic] width.
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it's = it is
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