p=2b+2h=48
b+h=24
h = 24-b
Area = bh = b(24-b)
b h Area
--------------
6 18 108
8 16 128
12 12 144
16 8 128
"Conjecture": The area appears to be maximum when the length and width are equal.
In fact this is the case; and it is easily proven.
Let the base be 12+x and the height be 12-x; that makes base plus height 24, so the perimeter is 48.
The area is then (12+x)(12-x)=144-x^2; that area is maximum when x=0, making the base 12+0=12 and the height 12-0=12.