Hi



a rectangle has a diagonal of 5in and a length of 4in.

Pythagorean Theorem:  a^2 + b^2 = c^2

Let x be the width

4^2 + x^2 = 5^2   |Diagonal being 5"

x^2 = 25-16

x^2 = 9in^2

x = ± 3

Width = 3in   |Tossing out the Negative Solution of -3  for Length

Wish You the Best in your Studies. 

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
 

a rectangle has a diagonal of 5in and a length of 4in.find the length of the width

That's one of the few Pythagorean Triples, a 3-4-5, which makes the width, 3 inches. 

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