SOLUTION: The width of a rectangle is 16 ft less than the length. The area is 10 ft^2. Find the length and the width.

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Question 1158688: The width of a rectangle is 16 ft less than the length. The area is 10 ft^2. Find the length and the width.
Found 2 solutions by Shin123, josgarithmetic:
Answer by Shin123(626)   (Show Source): You can put this solution on YOUR website!
Let the length and width of the rectangle be l and w, respectively. We have . Substituting l-16 for w in the second equation, we get . Expanding and rearranging, we get .
Solved by pluggable solver: Completing the Square for Quadratics
To complete the square for the quadratic , we must first find a square which when expanded, has x2 and -16x in it.
is the square we are looking for. Expanding gets . So we have . So completing the square gives . Adding 74 from both sides, we get . Taking the square root of both sides gives . So the solutions are x=16.6023252670426 and x=-0.602325267042627.
We pick the positive solution, . So the length is . The width is .
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
L, length
L-16, width
10, area in square feet



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Solving that you find .
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