SOLUTION: the perimeter of a rectangle parking lot is 320m.If the length of the parking lot is 95m,what is the width?
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Question 1151486: the perimeter of a rectangle parking lot is 320m.If the length of the parking lot is 95m,what is the width?
Found 2 solutions by jim_thompson5910, greenestamps:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
P = 2*(L+W) is the perimeter of a rectangle with length L and width W
L = 95 and W is unknown. P = 320 is the given perimeter
P = 2(L+W)
2(L+W) = P
2(95+W) = 320 .... plug in P = 320 and L = 95
2(95+W)/2 = 320/2 .... divide both sides by 2
95+W = 160
W+95 = 160
W+95-95 = 160-95 ... subtract 95 from both sides
W = 65
Answer: The width is 65 meters
Check:
P = 2(L+W)
P = 2(95+65)
P = 2(160)
P = 320
We get the proper perimeter, so the answer is confirmed.
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangle is twice the length plus twice the width. (When you walk around the perimeter of a rectangular field, you travel the length twice and the width twice.)
So half the perimeter is the length plus the width once each. (When you walk halfway around that rectangular field, you walk the length once and the width once.)
The given perimeter is 320m, so half the perimeter is 160m.
That 160m is the length (95m) plus the width; so the width is 160-95 = 65m.
With formal algebra, that solution looks something like this:
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