SOLUTION: Area of original rectangle is 12 x²+11x-5f t² Area is changed by decreasing the length by 2ft and increasing the width by 4ft. Find the new area *remember the length is always

Question 1137426: Area of original rectangle is 12 x²+11x-5f t² Area is changed by decreasing the length by 2ft and increasing the width by 4ft. Find the new area
*remember the length is always the longer side.

Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!

Area of original rectangle is
....factor completely to find expressions for length and width

let
=> be the length
=> be the width

Area is changed by:

the length by ft =>=>
and the width by ft=>=>
the new area is:
.....expand

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Area of original rectangle is 12 x²+11x-5f t² Area is changed by decreasing the length by 2ft and increasing the width by 4ft. Find the new area
*remember the length is always the longer side.

Factoring the trinomial results in: (4x + 5)(3x - 1).
Looking at both expressions/binomials, it's OBVIOUS that 4x + 5 is UNEQUIVOCALLY the LARGER EXPRESSION,
and so, when the adjustments to the dimensions are made, we get the following trinomial for the ADJUSTED area:
ACCEPT no other answer!
There're many people in this forum who do nothing else but produce INCORRECT answers to problems. Sometimes they leave and I'm sure others who
do provide the correct help hope that they NEVER return, but somehow they always manage to. In the best interest of the people who seek help, I
would hope that they either learn to do math and get the correct answers or simply JUST DISAPPEAR!
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