SOLUTION: Area and parameter of rectangle is 6000 and 340 then length of parameters

Question 1129657: Area and parameter of rectangle is 6000 and 340 then length of parameters

Found 2 solutions by solver91311, MathLover1:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

You used the word "parameter" twice, once completely incorrectly and once in a very confusing way. I presume you meant to say: The area of a rectangle is 6000 square units and the perimeter is 340 units. What are the measures of the length and width? If English is a second language for you, please try to get help from someone more fluent before posting the next time.

Let and represent the dimensions of the rectangle. Then:

Area = and Perimeter = . Hence:

So

Put the quadratic into standard form and solve for , then calculate

John

My calculator said it, I believe it, that settles it

Answer by MathLover1(20855) (Show Source): You can put this solution on YOUR website!

Area of rectangle is :

........eq.1

and perimeter is :

.......eq.2

from eq.1 and eq.2

solutions:
if =>
if =>

so, or

then
=>=>
=>=>
=> or

since length is greater than width, then length of rectangle is and the width is

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