SOLUTION: The length of a rectangle is 3 less than 5 times the width. the perimeter is 10 times the width find the demensions.

Question 1129485: The length of a rectangle is 3 less than 5 times the width. the perimeter is 10 times the width find the demensions.

Found 4 solutions by josgarithmetic, MathTherapy, ikleyn, greenestamps:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
length, 5x-3
width , x
perimeter, 10x

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

The length of a rectangle is 3 less than 5 times the width. the perimeter is 10 times the width find the demensions.

As usual, IGNORE the RUBBISH posted by the other person.
Dimensions:
<===== This will NEVER get you a correct answer!!
Answer by ikleyn(52787)   (Show Source): You can put this solution on YOUR website!
.

Let x be the width; then the length is (5x-3). The equation is x + (5x-3) + x + (5x-3) = 10x Simplify and solve for x: 12x - 6 = 10x 12x - 10x = 6 2x = 6 x = 6/2 = 3 - the width. ANSWER 5x-3 = 5*3-3 = 12 - the length. ANSWER

Solved.

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!

Let the width be w. Then the problem tells us the length is 3 less than 5 times the width:

l = 5w-3

We are also told that the perimeter (2l+2w) is 10 times the width:

2l+2w = 10w
2l = 8w
l = 4w

We have two different expressions for the length in terms of the width; those two expressions must be equal:

5w-3 = 4w
w = 3

l = 4w = 12

The rectangle is 12x3.
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