SOLUTION: the length of a rectangle is 8 meters more than the width. if both rhe width and length were doubled, the area would be 192 square meters. Find the dimensions of the original recta
The original dimensions are x and x-8 meters.
The doubled dimensions are 2x and 2*(x-8).
You are given that (2x)*(2*(x-8) = 192 <<<---=== area
Simplify and solve this quadratic equation.
First step in simplifying is to divide both sides by 4.