SOLUTION: The area of a rectangle is 65yd^2 and the length is 3yd less than double the width. What are tye dimensions

Question 1119829: The area of a rectangle is 65yd^2 and the length is 3yd less than double the width. What are tye dimensions

Found 2 solutions by Alan3354, Shin123:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The area of a rectangle is 65yd^2 and the length is 3yd less than double the width. What are tye dimensions
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Area = W*L = 65
W*(2W-3) = 65
2W^2 - 3W - 65 = 0
Solve for W, then for L
Answer by Shin123(626) (Show Source): You can put this solution on YOUR website!

or The dimensions are 6.5 and 10. Check: 6.5*2=13-3=10 6.5*10=65
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