SOLUTION: The length of a rectangle is 3ft less than twice the width and the area of the rectangle is 14ft^2. Find the dimensions of the rectangle.
Algebra.Com
Question 1109955: The length of a rectangle is 3ft less than twice the width and the area of the rectangle is 14ft^2. Find the dimensions of the rectangle.
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
Let w be the width of the rectangle, and 2w-3 be the length. Then:
w(2w-3)=14
2w²-3w-14=0
(2w-7)(w+2)=0
w=7/2 or -2
The width is 3-1/2 ft, the length is 4 ft.
☺☺☺☺
RELATED QUESTIONS
The area of a rectangle is 65ft squared, and the length of the rectangle is 3ft less than (answered by josgarithmetic)
Problem Page The area of a rectangle is 65ft^2 and the length of the rectangle is 3ft... (answered by josgarithmetic,ikleyn,stanbon)
The width of a rectangle is 3ft less than the length. The area 4ft Find the length and... (answered by stanbon)
The length of a rectangle is 3m less than twice the width, and the area of the rectangle (answered by josgarithmetic)
The length of a rectangle is 3yd less than twice the width, and the area of the rectangle (answered by josgarithmetic,MathTherapy)
The length of a rectangle is 3m less than twice the width, and the area of the rectangle... (answered by josgarithmetic)
The area of a rectangle is 53m^2 and the length of the rectangle is 5 m less than twice... (answered by MathLover1)
The length of a rectangle is 3m less than twice the width, and the area of the rectangle... (answered by mananth)
The perimeter of a rectangle is 46 feet. The width is 3ft less than twice the length.... (answered by oscargut)