SOLUTION: The perimeter of a rectangle is 52 feet. The length is 2 feet more than 5 times the width. Find the dimensions of the rectangle.

Question 1103214: The perimeter of a rectangle is 52 feet. The length is 2 feet more than 5 times the width. Find the dimensions of the rectangle.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
-------------------------------------------
The perimeter of a rectangle is 52 feet.
-------------------------------------------

p=52
L, length
w, width
p=2w+2L

----------------------------------------------------
The length is 2 feet more than 5 times the width.
---------------------------------------------------

L=5w+2

-------------------------------------------------
Find the dimensions of the rectangle.
-------------------------------------------------

Do that. All the basic starting data is ready. Just a couple of substitutions and a few simple algebra steps.
RELATED QUESTIONS
The length of a rectangle is 5 feet more than seven times the width. The perimeter is 154 (answered by ikleyn)

The perimeter of a rectangle is 46 feet. The length is 5 feet more than the width. Find... (answered by Aldorozos)

the perimeter of a rectangle is 52 feet. the length is 2 feet shorter than three times... (answered by Seutip)

The length of a rectangle is 5 feet more than twice its width. Find the dimensions of the (answered by algebrahouse.com)

The perimeter of a rectangle is 50 feet. If the length is 2 more than 3... (answered by solver91311)

the length of a rectangle is 2 more than 3 times the width. if the perimeter is 36 feet,... (answered by TimothyLamb)

the perimeter of a rectangle is 36 feet. the length is 2 feet more than three times the... (answered by Hawksfan)

The length of a rectangle is 2 feet more than five times its width. The perimeter of the (answered by elima)

The length of a rectangle is 2 feet more than twice the width. The perimeter is 34 feet.... (answered by solver91311)