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the perimeter of a rectangular garden is 420 cm . If its length is increased by 20% and breadth is decreased by 40 % ,
we get the same perimeter. then the length and breadth of the new formed rectangular garden , respectively are
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The solution by @josgarithmetic is not correct. The correct solution is placed below.
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Let L be the length and W be the width of the rectangular garden (the original dimensions).
Then the first equation is
2L + 2W = 420, or L + W = 210.
The second equation is
2*(1.2L) + 2*(0.6W) = 420, or 1.2L + 0.6W = 210.
So, you have the system of 2 equations in 2 unknowns
L + W = 210, (1)
1.2L + 0.6W = 210. (2)
From eq(1) express W = 210-L and substitute it into eq(2). You will get
1.2L + 0.6*(210-L) = 210,
1.2L + 0.6*210 - 0.6L = 210 ====> 0.6L = 210 - 0.6*210 = 0.4*210 ====> L = = 140.
Thus we just found L = 140 cm.
Then W = 210 - L = 210 - 140 = 70 cm.
The original length was 140 cm. The original width was 70 cm.
Check. 140 + 70 + 140 + 70 = 420. ! Correct !
2*140*1.2 + 2*70*0.6 = 420. ! Correct !
The new dimensions are: 1.2*L = 1.2*140 = 168 cm (length) and 0.6*W = 0.6*70 = 42 cm.
Answer. The new dimensions are: 168 cm (length) and 42 cm (width).
Solved.