SOLUTION: The length of a rectangle is 2 yd more than twice the width x. The area is 544yd^2. Find the dimensions of the given shape.
Algebra.Com
Question 1102142: The length of a rectangle is 2 yd more than twice the width x. The area is 544yd^2. Find the dimensions of the given shape.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 2 yd more than twice the width x. The area is 544yd^2. Find the dimensions of the given shape.
--------------------
x*(2x+2) = 544
x*(x+1) = 272
-----
Find 2 consecutive integers with a product of 272
---------
Hint:
1 will be more than sqrt(272), one will be less.
RELATED QUESTIONS
The length of a rectangle is 1 yd more than twice its width, and the area of the... (answered by checkley77)
The area of a rectangle is 54 yd^2 , and the length of the rectangle is 3 yd more than... (answered by TimothyLamb)
the area of a rectangle is 54 yd^2,and the length of the rectangle is 3 yd more than... (answered by ikleyn)
the length of a rectangle is 3 yd less than twice its width, and the area of the... (answered by Cromlix)
the area of a rectangle is 99 yd^2, and the length of the rectangle is 7 yd more than... (answered by TimothyLamb)
the length of a rectangle is 3 yd less than twice the width, and the area of the... (answered by TimothyLamb)
The length of a rectangle is 1 yd less than twice the width, and the area of the... (answered by MathLover1,Alan3354,ikleyn)
The length of a rectangle is 3 yd less than twice the width, and the area of the... (answered by Cromlix)
the length of a rectangle is twice the width. the area is 32 yd^2. find the length and... (answered by checkley77)