SOLUTION: Find the dimensions of a rectangle whose width is 11 meters less than its length, and whose area is 672 square meters.

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Question 1098095: Find the dimensions of a rectangle whose width is 11 meters less than its length, and whose area is 672 square meters.
Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
length=x
width=x(x-11)
x(x-11)=672
x^2-11x-672=0
(x-32)(x+21)=0
x=32, -21, positive root only
length is 32 meters
width is 21 meters
product is 672 m^2.
Answer by MathTherapy(10556)   (Show Source): You can put this solution on YOUR website!

Find the dimensions of a rectangle whose width is 11 meters less than its length, and whose area is 672 square meters.
For these types of problems, you DON'T need to form a quadratic equation and solve it. You just need to find 2 factors of 672 with a difference of 11.

Unless of course, you can't find those factors, in which case you use the formula, or you can complete the square to find one of the factors, and use

that to find the other. 

Be aware though that you'll be dealing with larger numbers if any of the latter is chosen. 

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