SOLUTION: A rectangle with an area of 64 cm² has a length that is 8 cm more than twice it's with. Find the length, width and perimeter of the rectangle.
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Question 1080632: A rectangle with an area of 64 cm² has a length that is 8 cm more than twice it's with. Find the length, width and perimeter of the rectangle.
Answer by rapture(86) (Show Source): You can put this solution on YOUR website!
Length = 2x + 8
Width = x
Area = 64
Solve 64 = x(2x + 8) for x.
Then plug x-value into
P = 2(2x + 8) + 2x to find the perimeter.
You finish.
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