SOLUTION: the perimeter of a rectangle is 40 inches and its area is 91 square inches find the length and width of the rectangle. solve step by step. There are 10 steps
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Question 1077369: the perimeter of a rectangle is 40 inches and its area is 91 square inches find the length and width of the rectangle. solve step by step. There are 10 steps
Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!
2L + 2W = 40 (1) —> L+W=20
LW = 91 (2)
L = 91/W —> Substitute this into (1):
(91/W) + W = 20
<— multiplied both sides by W
W=7 or W=13
W=7 —> L=13
W=13 —> L=7 (let's reject this as L>W is the convention when describing rectangles)
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Ans: L=13in, W=7in
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Check: Area = LxW = 13in*7in = 91 sq in (ok)
Perimeter = 2L+2W=2(13in) + 2(7in) = 26in+14in = 40in (ok)
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