SOLUTION: The perimeter of a rectangle is 234ft. When its length is doubled, the perimeter increases by 58ft.
Use elimination to determine the dimensions of the rectangle.
Algebra.Com
Question 1076486: The perimeter of a rectangle is 234ft. When its length is doubled, the perimeter increases by 58ft.
Use elimination to determine the dimensions of the rectangle.
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
P=2L+2W
2L+2W=234
2(2L)+2W=234+58=292
4L+2W=292
2L+2W=234
2L=58
L=29
W=88
The dimensions of the rectangle are 29X88 ft. ☺☺☺☺
RELATED QUESTIONS
The length of a rectangle is 5 more than its width. If perimeter is 58ft, what are length (answered by stanbon)
the perimeter of a rectangle is 58ft. the length is 5 feet more than 2 times the width.... (answered by ewatrrr)
A rectangle length is 10 less than 4 times its with. A new rectangle is formed when the... (answered by sachi)
The width of a rectangle is 5 times its length. If the width of the rectangle is doubled, (answered by mananth)
The volume of rectangle is 234ft with a base that is 13ft by 13ft, what is the height... (answered by vleith)
the perimeter of a rectangle is 108 cm. If the length is increased by 5 and the width is... (answered by rothauserc)
the perimeter of a rectangle is 108 cm. If the length is increased by 5 and the width is... (answered by fractalier)
The length of a certain rectangle is 10 meters greater than twice its width. if its... (answered by checkley77)
the length of a rectangle exceeds its width by 4 feet. if the width is doubled and the... (answered by ankor@dixie-net.com)