SOLUTION: the perimeter of the rectangle if the width is twice the root of the length and the area is 250

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Question 1076140: the perimeter of the rectangle if the width is twice the root of the length and the area is 250
Found 3 solutions by mananth, ikleyn, josgarithmetic:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
the width is twice the root of the length and the area is 250
length be x
width =
Area = 250
x*2sqrt(x)=250
square both sides
4x^3= 250*250
x^3= 125*125
x = sqrt(125*125)
x=25 the length
width = 2*sqrt(x)
= 2*sqrt(25)
=10 the width



Answer by ikleyn(52780)   (Show Source): You can put this solution on YOUR website!
.
the perimeter of the rectangle if the width is twice the root of the length and the area is 250.
~~~~~~~~~~~~~~~~~~~


        The answer in the post by @mananth is correct,  but on the way he made errors
        that shocked me.  I afraid that they shoked you,  too.
        Therefore,  I came to present the solution in a correct form.
        Read my solution attentively;  watch every my step and find the differences between
        my solution and that by @mananth.


Let the length be x.

Then the width = .

Area = 250:   = 250.

Square both sides

    4x^3 = 250*250,

    x^3 = 125*125 =  = ,

    x =  = 25  the length.

    width =  =  = 2*5 = 10.

    the width = 10.


The perimeter = 25 + 10 + 25 + 10 = 70.    ANSWER

Solved.



Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
---------------------------------------------------------------
the width is twice the root of the length and the area is 250.
---------------------------------------------------------------

L, length
2sqrt(L), width






------length

------the given area

------width

Question asked for perimeter.


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