SOLUTION: Somebody solve this please........the length of a rectangular mailing label is 5 centimeters less than twice the width. The perimeter is 38 centimeters. Find the dimensions of the
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Question 1064739: Somebody solve this please........the length of a rectangular mailing label is 5 centimeters less than twice the width. The perimeter is 38 centimeters. Find the dimensions of the label......
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Let x be the width
"The length of a rectangular mailing label is 5 centimeters less than twice the width" means that the length is 2x-5
We have these three facts:
W = x
L = 2x-5
P = 38
We'll use those three facts above to find x. The formula used is the rectangle perimeter formula
P = 2*(L+W)
38 = 2*(x+2x-5) ... substitute (see equations above)
38 = 2*(3x-5)
38 = 2*(3x)+2(-5)
38 = 6x-10
6x-10 = 38
6x-10+10 = 38+10
6x = 48
6x/6 = 48/6
x = 8
--------------------
We know now that x = 8. So the width is 8 cm. Recall that at the top we let x = width.
The length is L = 2x-5 = 2*8-5 = 16-5 = 11 cm
--------------------
In summary, the dimensions are 11 cm by 8 cm
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