SOLUTION: The perimeter of a rectangular picture frame is 30 inches. The length of the frame is three less than twice the width. What are the dimensions of the frame?

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Question 1059741: The perimeter of a rectangular picture frame is 30 inches. The length of the frame is three less than twice the width. What are the dimensions of the frame?
Answer by ikleyn(52847)   (Show Source): You can put this solution on YOUR website!
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The perimeter of a rectangular picture frame is 30 inches. The length of the frame is three less than twice the width.
What are the dimensions of the frame?
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Let L be the length, W be the width.
Then the condition says:

L = 2W - 3.

The perimeter is L + W + L + W.

Substitute (2W-3) instead of L in the perimeter.

You will get for the perimeter this expression: (2W-3) + W + (2W-3) + W.

Or, combining the like terms, 6W - 6.

It is equal to 30, according to the condition:

6W - 6 = 30.

Then 6W = 30 + 6,

6W = 36,

W = 6 inches.

So, you just found the width. It is 6 inches.

Now, the length is 2W -3 = 2*6-3 = 9 inches.


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