SOLUTION: If the perimeter of a rectangle is 54 cm and the area is 182 square cm, then what are the dimensions of the rectangle?
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Question 1059568: If the perimeter of a rectangle is 54 cm and the area is 182 square cm, then what are the dimensions of the rectangle?
Found 3 solutions by Alan3354, stanbon, MathTherapy:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
If the perimeter of a rectangle is 54 cm and the area is 182 square cm, then what are the dimensions of the rectangle?
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P = 2L + 2W = 54
L + W = 27
L*W = 182
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Find a pair of factors of 182 with a sum of 27.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If the perimeter of a rectangle is 54 cm and the area is 182 square cm, then what are the dimensions of the rectangle?
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54 = 2(L + W)
L*W = 182
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L + W = 27
L = 27-W
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Substitute for "L" and solve for "W"::
(27-W)W = 182
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-W^2 + 27W - 182 = 0
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W^2 - 27W + 182 = 0
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W = 32.59 (Width)
L = 182/32.59 = 5.58 (Length)
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Cheers,
Stan H.
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
If the perimeter of a rectangle is 54 cm and the area is 182 square cm, then what are the dimensions of the rectangle?
Dimensions:
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