SOLUTION: The perimeter of a rectangle is 27 cm,and its area is 35 square cm.Find the length and then width of the rectangle.

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Question 1054756: The perimeter of a rectangle is 27 cm,and its area is 35 square cm.Find the length and then width of the rectangle.

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangle is 27 cm,and its area is 35 square cm.Find the length and then width of the rectangle.
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P = 2(L + W)
L*W = 35
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L = (P/2)-W
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Substitute for "L" and solve for "W":
[(P/2)-W]W = 35
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W^2 - (27/2)W +35 = 0
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W = [(27/2) +- sqrt[13.5^2 - 4*35]]/(2
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W = [13.5 +- 6.5]
Width = 7 cm
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Since L*W = 35, Length = 5 cm
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Cheers,
Stan H.
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