SOLUTION: If the area of the square is increased by 69% then the side of the square is increased by ???

Question 1046778: If the area of the square is increased by 69% then the side of the square is increased by ???
Found 2 solutions by addingup, ewatrrr:
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
Let the original area be A, the original side be s, and the new side be x:
A = s^2
If the area increased by 69%:
(1+0.69)A = (1.69)A
To find the length of the new side:
x^2=1.69A
Since A = s^2:
x^2 = 1.69l2
Taking the square root of both sides we get:
x = 1.30
x = (1+0.3)s
The increase in length is 0.30 or 30%
:
John

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
A = s^2
1.69A = s'^2 Substituting s^2 for A
Let s' represent the new side length
1.69s^2 = s'^2 Taking the square root and using positive root
1.3s = s'
the side of the square is increased by 30%
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