SOLUTION: Write the equation in standard form of the circle whose center is (3,-5) and passes through point (7,1)
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Question 1039381: Write the equation in standard form of the circle whose center is (3,-5) and passes through point (7,1)
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
Radius is the distance from center (3,-5) to the point on the circle, (7,1).
Just needs to be simplified.
Answer by ikleyn(52790) (Show Source): You can put this solution on YOUR website!
.
Write the equation in standard form of the circle whose center is (3,-5) and passes through point (7,1)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
The equation of the circle is
= ,
where "r" is the radius, or
= .
"r" is the distance from the center to the given point in the circle, which is
= = = 16 + 36 = 52.
Finally, the equation of the circle is
= .
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