SOLUTION: hey, how are you? I need help in this problem. The length of a rectangle is 3ft more than twice its width, and the area of the rectangle is 35ft. Find the dimensions of the rect

Algebra ->  Rectangles -> SOLUTION: hey, how are you? I need help in this problem. The length of a rectangle is 3ft more than twice its width, and the area of the rectangle is 35ft. Find the dimensions of the rect      Log On


   

Question 103706: hey, how are you? I need help in this problem.
The length of a rectangle is 3ft more than twice its width, and the area of the rectangle is 35ft. Find the dimensions of the rectangle.
thanks for your time.
Juan
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
let x=width, so 2x+3=length ... area=x(2x+3) ... 35=2x^2+3x

2x^2+3x-35=0 ... (2x-7)(x+5)=0 ... x=3.5 and x=-5 ... negative value not realistic