SOLUTION: The width of a rectangle is 8X. The perimetwr is 48X. Find the length of the rectangle in terms of variable x

Algebra.Com
Question 1034912: The width of a rectangle is 8X. The perimetwr is 48X. Find the length of the rectangle in terms of variable x
Answer by addingup(3677)   (Show Source): You can put this solution on YOUR website!
48x-2(8x)= 2(length)
RELATED QUESTIONS

the width of a rectangle is x+4. The length is 2x-9. Find the area of the rectangle in... (answered by nyc_function)
The length of a rectangle is ( 3x + 4 ) feet and the width is ( 2x - 6 ) feet. Find the... (answered by Fombitz)
the length of a rectangle is (5x) feet, and the width is (2x-7). find the area of the... (answered by nerdybill)
The length of a rectangle is (5x+1)ft. The width is (2x-1)ft. find the area of the... (answered by drk)
if the area of a rectangle is 48x^2 and its width is 8x whatis its... (answered by checkley79)
The width of a rectangle is (3x − 1) in. The length of the rectangle is twice... (answered by dragonwalker)
The length of a rectangle is 2x+3. The width is x-3. Express the area of the rectangle in (answered by checkley77)
The length of a rectangle is 3 in. More than its width. The perimeter of the rectangle... (answered by josgarithmetic)
The length of a rectangle is 3 in. more than its width. The perimeter of the rectangle is (answered by rfer,drj)