SOLUTION: The length of a rectangle is 3 centimeters less than its width. What are the dimensions of the rectangle if its area is 134 .

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Question 1029035: The length of a rectangle is 3 centimeters less than its width. What are the dimensions of the rectangle if its area is 134 .
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 3 centimeters less than its width. What are the dimensions of the rectangle if its area is 134 .
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L = W + 3
L*W = 134
w*(w+3) = 134
w^2 + 3w - 134 = 0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=545 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 10.1726175299288, -13.1726175299288. Here's your graph:

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W =~ 10.1726
L =~ 13.1726
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