SOLUTION: find the dimensions of a rectangle that has a perimeter of 208 feet if it's length is twice its width. this has to be a system of equations.

Question 1015348: find the dimensions of a rectangle that has a perimeter of 208 feet if it's length is twice its width. this has to be a system of equations.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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P=2(L+W)
208ft=2(L+W) . Equation 1
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L=2W . Equation 2
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Equations one and 2 are your system of equations.
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Substitute for L (from Equation 2) in Equation 1:
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208ft=2(L+W)
208ft=2(2W+W)
104ft=3W
34.67ft=W
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ANSWER 1: Width is 34.67 feet.
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L=2(W)=2(34.67ft)=69.33ft
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ANSWER 2: Length is 69.33 feet.
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