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The perimeter of rectangle is 80 dm. The width is 1 more than one half the length. Find the length and width of the rectangle.
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You need to solve this system of two equations
x + y = 40,
y - 1 = ,
where x is the length and y is the width.
Substitute y = 40 -x from (1) into (2).
You will get
(40 - x) - 1 = .
Multiply this equation by 2. You will get
80 - 2x - 2 = x, or
78 + x + 2x = 3x.
Hence, x = = 26 dm. It is the length.
The width is 40 - 26 = 14 dm.