SOLUTION: I have been trying to solve this question but I'm not following. A student earned a grade of 80 percent on a math test and got 32 correct how many problems did the student get wro

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Question 1012611: I have been trying to solve this question but I'm not following. A student earned a grade of 80 percent on a math test and got 32 correct how many problems did the student get wrong.
Found 3 solutions by rothauserc, MathTherapy, fractalier:
Answer by rothauserc(4718)   (Show Source): You can put this solution on YOUR website!
80 / 32 = 100 / x
80x = 3200
x = 40
therefore there were 40 questions on the test and
the student got 8 wrong
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

I have been trying to solve this question but I'm not following. A student earned a grade of 80 percent on a math test and got 32 correct how many problems did the student get wrong.
Let number of incorrect answers be I

Then number of questions on test = I + 32

We then get: 

.8(I + 32) = 32 ------ Cross-multiplying

.8I + 25.6 = 32

.8I = 32 - 25.6

.8I = 6.4

I, or number of incorrect answers = , or  

Answer by fractalier(6550)   (Show Source): You can put this solution on YOUR website!
 If the student got 80% correct and got 32 questions correct, then 80% of the total questions must be 32.  Call the total, x.  Then we can write

(.80)x = 32

x = 40 questions total

Thus the student missed 40-32 = 8 questions. 

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