SOLUTION: If the length of a rectangle is 3 feet more than the width and the area is 40m^2. What are the dimensions?
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Question 1007881: If the length of a rectangle is 3 feet more than the width and the area is 40m^2. What are the dimensions?
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call the length and width, L and W. Then we have
L = W + 3 and
Area A = LW = 40
Substituting in we get
(W + 3)W = 40
W^2 + 3W - 40 = 0
(W + 8)(W - 5) = 0
W = 5 feet and then
L = 8 feet
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