SOLUTION: Please help me solve this word problem:
A square mirror has sides measuring 2 ft less than the sides of a square painting. If the difference between their areas is 32 ft square
Algebra.Com
Question 1006415: Please help me solve this word problem:
A square mirror has sides measuring 2 ft less than the sides of a square painting. If the difference between their areas is 32 ft squared, find the lengths of the sides of the mirror and the painting.
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
= length of the side of the painting (in feet).
= length of the side of the mirror (in feet).
= area of the painting (in ft squared).
= area of the mirror (in ft squared).
The problem says that
,
because the difference of their areas is 32 ft squared,
and the mirror, with shorter sides, must have a smaller area.
Solving :
--->
The length of the sides of the mirror is , and
the length of the sides of the painting is .
RELATED QUESTIONS
A square mirror has sides measuring 2 ft. less than the sides of a square painting. If... (answered by checkley77)
a sqaure mirror has sides measuring 2 ft less than the sides of a square painting. if the (answered by Theo)
please help me solve this problem: a square poster has two sides measuring 2 ft less... (answered by mananth)
Please help me solve this trigo problem.
A parcel of land has sides measuring 175 ft.,... (answered by Edwin McCravy)
square poster has sides measuring 2ft less than the sides of a square sign. If the... (answered by CubeyThePenguin)
A square poster has sides measuring 2 feet less than the sides of a square sign. If the... (answered by ankor@dixie-net.com)
A square poster has sides measuring 2 feet less than the sides of a square sign. if the... (answered by mananth)
A square poster has sides measuring 2 feet less than the sides of a square sign. If the... (answered by jorel1380)
A square poster has sides measuring 2 feet less than the sides of a square sign. If the... (answered by josmiceli)