SOLUTION: The length of a rectangle is 5 ft longer than twice the width, if the perimeter is 58 ft, find the length and width of the rectangle
Algebra.Com
Question 1002744: The length of a rectangle is 5 ft longer than twice the width, if the perimeter is 58 ft, find the length and width of the rectangle
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call length and width, L and W.
P = 2L + 2W = 58
and
L = 5 + 2W
Substitute this into the first equation and get
2(5+2W) + 2W = 58
10 + 4W + 2W = 58
6W + 10 = 58
6W = 48
W = 8 ft
L = 21 ft
RELATED QUESTIONS
the length of a rectangle is 6 ft longer than twice the width. if the perimeter is 108... (answered by Cromlix)
The length of a rectangle is 6 ft. longer than twice the width. If the perimeter is 90... (answered by josgarithmetic,MathTherapy)
the length of a rectangle is 12 ft longer than twice the width. If the perimeter is 102 (answered by JulietG)
The length of a rectangle is 11 ft. longer than twice the width. If the perimeter is 94... (answered by Cromlix)
The length of a rectangle is 10 ft longer than twice the width. If the perimeter is 74... (answered by mathworm7271)
The length of a rectangle is 5 ft longer than twice the width. if the perimeter is 100ft, (answered by Roseghanezadeh)
the length of a rectangle is 6 ft longer than twice the width. if the perimeter is 66... (answered by FrankM)
10. The length of a rectangle is 11ft longer than twice the width. If the perimeter is... (answered by stanbon)
the length of a rectangle is 9ft longer than twice the width. if the perimeter is 114 ft, (answered by mathstutor494)