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Tutors Answer Your Questions about Rational-functions (FREE)
Question 143465: The view of rectangular box at the right shows three faces of the box. The areas of two of the faces are 30 cm squared and 48 cm squared. The volume of the box is 240 cm cubed. What is the area of the third face?
Click here to see answer by vleith(1977)   |
Question 143399: Here's the problem:
The shape of the Gateway Arch of the Jefferson National Expansion Memorial in St. Louis, Missouri, resembles the graph of the function f(x)= -.00635x^2+ 4.0005x-.007875, where x is in feet. Describe the shape of the Gateway arch.
Thanks for the help!
Click here to see answer by scott8148(3385)  |
Question 145014: Find all number for which the rational expression is not defined:
(d-2)/(7-d)
This is as far as I have gotten however I do not think I am going about this problem correctly. Please help.
= (d-2)/(-d+7)
= -d^2+2d+7d-14
= -d^2+9d-14
Click here to see answer by solver91311(5072)  |
Question 145077: Think of real-life situations that can be represented by a logarithmic function and an exponential function, translate the situation to the function, and solve the function and represent it graphically.
I again, am not good at all with word problems. anyone who could help. Thanks
Click here to see answer by stanbon(26295) |
Question 145096: hope someone can help me with this one
1.Radisson Electric Companys monthly bill includes a basic customer charge of $12.00, and a usage charge of $0.07 for each kilowatt hour of electricity supplied.
- Write an equation that can be used to determine the monthly bill, given the number of kilowatt hours h supplied.
-Determine the electric bill if 1850 kilowatt hours of electricity are supplied.
2. Consider the points (4, 1) and (7, 8).
(a) Find the midpoint of the line segment with the given endpoints.
(b) Find the distance between the points. Give an exact answer and also an approximation to three decimal places. Show some work.
Click here to see answer by stanbon(26295) |
Question 145209: 5: For questions 5 14: Solve each of the following for y in radians. Use a calculator for exercises 9 and 10, with 3.1416 as an approximation for π.
y = arctan 1
π/7
π/4
2π/5
2π/2
6: y = arcsin (sqrt 2)/2
π/4
4π/2
sqrt π
sqrt(4π)
7: y = arccot (-sqrt 3)/3
2/3π
-π
2π/3
π/9
8: y = arcos (-sqrt 3)/2
-6π
-3π/2
π/2
5π/6
9: y = arccot 1.804
.5062
.6
.4708
5.6
10: y = arccos -.3090
1.914
1.252
1.8849
.889
11: y = tan (arcsin -3/5)
4/3
3/5
-2/3
-3/4
12: y = cos (arccot 12/5)
-12/5
12/13
-4
Ύ
13: y = sin (arccos 2/3 + arctan 1)
(sqrt 10 + 2sqrt2)/6
10 + sqrt 2
6/(10 + 2sqrt2)
(sqrt 10 + sqrt2)
14: y= cos (arcsin ½ + arcsin 2/3)
(sqrt15 2)/6
(sqrt1/2)/15
2/3
-sqrt6
15: For questions 15 19: Solve each of the following equations for 0° ≤ θ < 360°.
2 cos θ = 1
280°
60°; 360°
40°
60°; 300°
16: (tan θ + 1) (sec θ 1/2) = 0
120°; 300°
135°; 315°
65°; 300°
215°
17: sin2 θ + 3 sin θ + 2 = 0
270°
275°; 215°
119°
207°
18: sin θ/cos θ = tan2 θ
0°; 45°; 90°; 180°; 225°
180°; 225°
0°; 45°; 180°; 225°
45°; 225°
19: 4 sin θ cos θ = 1
90°; 145°; 225°
15°; 75°; 195°; 225°
25°; 145°
90°; 275°; 95°; 325°
20: For questions 20-23: Solve each of the following for x.
3y = 2 cos x + 1
x = arccos ((3y 1)/2)
x = cos (3y/2)
x = 12
x = arccos ((2x +1)/3)
21: 2y = tan (x+3)
x = 2 arctan (y-3)
x = (arctan 2y) - 3
x = tan2 3
x = arctan (2/3)
22: Arctan x = arccot 1
x = 1
x = cot (2/3)
x = -1
x = 12
23: Arcsin x arccos 1 = π/3
x = (sqrt3)/2
x = 3/2
x = - π/3
x = 1
Click here to see answer by solver91311(5072) |
Question 145362: I am trying to work the following problem, but am unsure how to go about doing so.
Find all values of x if f(x)=-38:
f(x)=5x+21/x
This is what I have gotten so far:
f(x)=5(-38)+[21/(-38)]
f(x)=-190+(21/-38)
What do I do from here?
Click here to see answer by vleith(1977) |
Question 145552: E. Solve the problem.
A rectangular box with volume 468 cubic feet is built with a square base and top. The cost is $1.50 per square foot for the top and the bottom and $2.00 per square foot for the sides. Let x represent the length of a side of the base in feet. Express the cost of the box as a function of x and then graph this function. From the graph find the value of x, to the nearest hundredth of a foot, which will minimize the cost of the box.
F.
If an object is dropped from a tower, then the velocity, V (in feet per second), of the object after t seconds can be obtained by multiplying t by 32 and adding 10 to the result. Find V as a linear function of t, and use this function to evaluate V(3.3), the velocity of the object at time t = 3.3 seconds.
Click here to see answer by ankor@dixie-net.com(6693)  |
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