Tutors Answer Your Questions about Rational-functions (FREE)
Question 75970: A retailer bought a dress for $75 and wants to sell it at a profit of 40% of the selling price. What price should she ask for the dress?
I don't know how to set the problem up or really how to solve it.
This is cumlative review on page 386 #30
Click here to see answer by tutorcecilia(2152)  |
Question 76443: solve each equation:
(2x-5)(6x+1) =(3x+2)(4x-7)
i worked this out but i dont think i'm doing it right:
i foiled bothe sides and got this
12x^2 +2x-35= 12x^2-13x -14
from there i got 15x=21
and the answer would be 1 2/5 but i dont think its right...please help
Click here to see answer by checkley75(3666) |
Question 76441: sandy has a collection of 57 coins worth $10. They consist of nickels, dimes, and quarters. The number of quarters is 2 more than 3 times the number of nickels. HOw many coins of each kind does she have?
I can't figure this out. Please help
on page 386
Click here to see answer by scott8148(6628)  |
Question 76807: +
Can you please help me simplify this by combining like radical terms, if possible. I am just confused about how to start the equation. I think I get the second part of the equation, but the first part is confusing to me. Could you please explain it all to me? Thank you.
Click here to see answer by funmath(2925) |
Question 76807: +
Can you please help me simplify this by combining like radical terms, if possible. I am just confused about how to start the equation. I think I get the second part of the equation, but the first part is confusing to me. Could you please explain it all to me? Thank you.
Click here to see answer by dkspoet(13) |
Question 76937: -
I had a problem similiar to this that used x-1 in place of the x^3 and the 9(for this other problem). Does that make sense? Im sorry if it doesn't. That was the way I was told to it was answered, but it doesn't seem right if I use it for this equation too. I had thought maybe, in this equation, that you might use x+1 in place of the x^2 and the 4. Am I on the right on track or totally off? I would really appreciate the help. Thankx
Click here to see answer by Earlsdon(6287) |
Question 77022: My problem is 5 over 6x minus 8 over 2x = x over 4
I know that you find the common denominator of 12x and multiply everything by it, I come up with the answer 10-48=3x^2; and I can't get any farther. I know there is more that I need to do, please help.
Click here to see answer by jim_thompson5910(28598) |
Question 77029: my problem is 5x-8 over x+2 = 5x-1 over x+3.
my gcd is (x+2)(x+3) and I know that I multiply everything by it. I come up with 5x^2+15=5X^2+10, then I get 5x^2+5=5x^2, I don't know what to do after that, or even if I done it right up to that point. I appreciate your help.
Click here to see answer by jim_thompson5910(28598) |
Question 76974: * 3
For this one, I am just not sure what to do with the 3 that is in front of the second square root. And because the first one doesn't have any number before it, I dont know if I have to get rid of it or leave it. Thanks.
Click here to see answer by checkley75(3666) |
Question 77195: - = 1
I am supposed to solve the radical equations for the variable. I started out by thinking I should separate each of the numbers and factor as best I could. So then I had:
* + 7 - + = 1
After that, I didn't think that the could cancel each other out because then there would be no variable, so I am currently stuck right there. I would be really grateful if you let me know if I am on the right track, or if I am really off, help me get on track. Thank you.
Click here to see answer by stanbon(57387) |
Question 77196: = (k + 8)
I am supposed to figure out what the variable is. So far, I have squared both sides so the "50 + 7k" is no longer a square root. and the k is squared and 8 is now 64. From there, I subtracted 50 from both sides, but then I got to a place where I had to find the square root of "7k" and then i got totally lost. Would you be able to help me? Thank you.
Click here to see answer by avidreader27(9) |
Question 77196: = (k + 8)
I am supposed to figure out what the variable is. So far, I have squared both sides so the "50 + 7k" is no longer a square root. and the k is squared and 8 is now 64. From there, I subtracted 50 from both sides, but then I got to a place where I had to find the square root of "7k" and then i got totally lost. Would you be able to help me? Thank you.
Click here to see answer by tutorcecilia(2152)  |
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