SOLUTION: 4th root of -256
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Question 987077: 4th root of -256
Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
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Notice that -256 = 256(cos(180°) + i*sin(180°)) and 256 = .
The roots of degree 4 of -256 are 4 complex numbers
1) 4(cos(45°) + i*sin(45°)) = = ; (Notice that 45° = 180°/4)
2) 4(cos(45°+90°) + i*sin(45°+90°)) = 4(cos(135°) + i*sin(135°)) = = ; (Notice that 90° = 360°/4)
3) 4(cos(45°+180°) + i*sin(45°+180°)) = 4(cos(225°) + i*sin(225°)) = = ;
4) 4(cos(45°+270°) + i*sin(45°+270°)) = 4(cos(315°) + i*sin(315°)) = = .
If you want to see my lessons on complex numbers in this site, look in this
- REVIEW of lessons on complex numbers
and especially in this one
- How to take a root of a complex number.
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