SOLUTION: Use the limit process to find the slope of the graph of {{{4x-2x^2}}} at (8, -96)
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Question 980452: Use the limit process to find the slope of the graph of at (8, -96)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Take the limit of the difference quotient as 
approaches zero.
\ =\ \lim_{h\right0}\, \frac{\[4(x+h)\,-\,2(x+h)^2\]\,-\,\[4x\,-\,2x^2\]}{h})
\ =\ \lim_{h\right0}\, \frac{4x\,+\,4h\,-\,2x^2\,-\,4xh\,-\,2h^2\,-\,4x\,+\,2x^2}{h})
\ =\ \lim_{h\right0}\, \frac{4h\,-\,4xh\,-\,2h^2}{h})
\ =\ \lim_{h\right0}\, 4\,-\,4x\,-\,2h)
\ =\ 4\,-\,4x)
Just evaluate )
John
My calculator said it, I believe it, that settles it
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