SOLUTION: Please please help!!!!
h(x)=((x^2)(e^x))/x
The function h is defined above. Which of the following are true about the graph of y=h(x)?
-The graph has a vertical asymptote at x=0
Algebra.Com
Question 973458: Please please help!!!!
h(x)=((x^2)(e^x))/x
The function h is defined above. Which of the following are true about the graph of y=h(x)?
-The graph has a vertical asymptote at x=0
-The graph has a horizontal asymptote at y=0
-The graph has a minimum point
I know the minimum point is correct but the booklet is telling me that graph has a horizontal asymptote y=0 but I believe that is not true because for it to y=0 the denominator leading coefficient exponent value must be greater then the numerator value which is not the case unless I'm missing something. Thank you!!!
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
The curve approaches the x axis from the bottom
(the origin is not included in the graph, due to divide by zero)
which means the value for y is growing as x approaches negative infinity.
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