SOLUTION: A circle has an equation x^2+y^2-3x-4y+4=0 Graph the circle using the center (h,k) and radius r. Find the intercepts, if any, of the graph.

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Question 970939: A circle has an equation
x^2+y^2-3x-4y+4=0
Graph the circle using the center (h,k) and radius r. Find the intercepts, if any, of the graph.

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Complete the Squares, and make use of the standard form of the finished equation.

-----THE MISTAKE HERE-.



------This will not work. This is not a real circle.
---No good.

Look for any mistakes in your given equation or in my steps. I found none in mine but examine if you want.
-
EDIT: FOUND THE MISTAKE IN MY WORK.

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
A circle has an equation
x^2+y^2-3x-4y+4=0
Graph the circle using the center (h,k) and radius r. Find the intercepts, if any, of the graph.


------- Grouping variables



Since the center-radius form of the equation of a circle is: ,
it's obvious that the center, or (h, k) = (, 2)
Since , then r, or radius = , or
Based on this info, you should be able to graph the circle.
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