Although the other tutor got the right answer, she is incorrect
for multiplying both sides of the inequality by the variable x.
That's because a variable x might not be positive, and if you
multiply through by a negative, that would reverse the > to <.
Also she did not use test values on the intervals.  

Here is a correct solution:

Get 0 on the right side by subtracting  from both sides:



Get the LCD = x on the left side:





Factor the numerator on the left:



We find all the critical numbers.  They are the values
obtained by setting the numerator=0 and the denominator=0

The numerator (7x-9)(9x+7) when set equal to 0 gives 
critical numbers  and 
The denominator x when set equal to 0 gives the critical
number 0.

We draw a number line and mark the critical numbers on it,
in order from smallest to largest.

-----o------o--------------------o--------------
   -7/9     0                   9/7    

We have 4 intervals to test by substituting a test point in the interval:
1. Left of , which is 
2. Between  and , which is 
3. Between  and , which is 
4. Right of , which is 

1. The easiest number in  to test in the original is x = -1



 

That's false so the solution set does not include 

2. The easiest number in  to test in the original is x = -.1



 

That's true so the solution set does include 

3. The easiest number in  to test in the original is x = 1



 

That's true so the solution set does include 

3. The easiest number in  to test in the original is x = 2



 

That's true so the solution set does include 

None of the critical numbers are part of the solution since the
symbol is > and not ≥.

So the solution set is:

No because if we substitute x=0,



It is meaningless to divide by zero.

No because the symbol is > and not ≥

Edwin